Shortcut of Heights and Distances


Shortcut 85:
Using tanƟ
Ɵ                                tan

0                                    0

30                            1/\sqrt3

45                                  1

60                              \sqrt3

90                              \infty
Question:
A man on a boat saw a tower of height 100m at an angle of 60o. What is the distance between the man and the tower?
Answer:
2b1
tanƟ = opp/adj
tan 60 = 100/x
√3 = 100/x
x= 100/√3

Shortcut 86:
Using Pythagoras theorem
 hyp^2=opp^2+adj^2
Question:
A man looks at the top of a tower which is 400m height. The minimum distance between him and top of the tower is 500m. What is the distance between him and the base of the tower?
Answer:
2c1
hyp2 = opp2 + adj2
5002 = 4002 + x2
x2 = 90000
x = 300 m

Comments

Comments 0

Your email address will not be published. Required fields are marked *

Shortcut of Heights and Distances

log in

Don't have an account?
sign up

reset password

Back to
log in

sign up

Back to
log in