**Shortcut 50:**

Train crossing a pole

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Question:

A train of length 450m is travelling at a speed of 54kmph. How long will it take to cross a pole?

Answer:

Speed of train ST in m/s = 54x(5/18)

= 15mps

Length of train = LT = 450m

Time taken to cross = 450/15

= 30 seconds

**Shortcut 51:**

Time taken to cross a platform or bridge

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Question:

A train of length 200m crosses a platform of length 150m at a speed of 72kmph. How long will the train take to cross the platform?

Answer:

LT = 200m

LP = 150m

ST = 72x(5/18) = 20mps

Time taken to cross the platform = (200+150)/20

= 17.5 seconds

**Shortcut 52:**

Trains crossing another train in opposite direction

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Question:

Two trains A and B of length 200m and 300 are travelling at a speed of 54kmph and 36kmph respectively in opposite directions. How long will they take to cross each other?

Answer:

L1 = 200; L2 = 300

S1 = 54kmph = 54(5/18)mps = 15mps

S2 = 36kmph = 36(5/18)mps = 10mps

Substitute the values in the above equation, we get

T = (200+300)/(15+10)

= 20 seconds

**Shortcut 53:**

Two trains crossing each other in same direction

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Question:

Two trains A and B of length 200m and 300 are travelling at a speed of 54kmph and 36kmph respectively in same directions. How long will they take to cross each other?

Answer:

L1 = 200; L2 = 300

S1 = 54kmph = 54(5/18)mps = 15mps

S2 = 36kmph = 36(5/18)mps = 10mps

Substitute the values in the above equation, we get

T = (200+300)/(15-10)

= 100 seconds

**Shortcut 54:**

Train crossing a man on another train in opposite direction

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Question:

Two trains A and B of length 300m and 400 are travelling at a speed of 72kmph and 36kmph respectively in opposite directions. How long will train A take to cross a man travelling in train B?

Answer:

LT = 300, (Length of train crossing the man)

S1 = 72kmph = 72(5/18)mps = 20mps

S2 = speed of the man travelling in train B

S2 = 36kmph = 36(5/18)mps = 10mps

Substitute the values in the above equation, we get

T = (300)/(20+10)

= 10 seconds

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